What is the interquartile range of the data set?
5, 5, 6, 7, 9, 11, 14, 17, 21, 23
A. 18
B. 9
C. 11
D. 10
PLZ HELP
Q2 is the median: 10
Q1 is the median of the 1st half: 6
Q3 is the median of the 2nd half: 17
The IQ range is Q3-Q1 = 11
Google can provide you with man explanations and examples.
The data sets below show the quiz scores for two classes.
Class A: 89 94 91 92 93 89
Class B: 71 70 85 81 75
Which of the following statements correctly describes the degree of variability of the classes?
A. Class A has a higher degree of variability because its range is 3 times larger than the range of Class B.
B. Class B has a higher degree of variability because its range is 3 times larger than the range of Class A.
C. Class A and B have the same degree of variability because they have the same range. HELP
this is not even the question i searched lol
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To find the interquartile range of a data set, we first need to determine the values of the first quartile (Q1) and the third quartile (Q3). Then, we subtract Q1 from Q3 to get the interquartile range.
1. Start by ordering the data set in ascending order:
5, 5, 6, 7, 9, 11, 14, 17, 21, 23
2. Calculate the median (Q2), which is the middle value of the data set. In this case, since we have 10 data points, the median is the average of the 5th and 6th values:
Median (Q2) = (9 + 11) / 2 = 10
3. Next, divide the data set into two halves. For the lower half, find the median (Q1) of that portion. In this case, the lower half is:
5, 5, 6, 7, 9
Since we have 5 data points in the lower half, the median is the average of the 2nd and 3rd values:
Lower Median (Q1) = (5 + 6) / 2 = 5.5
4. For the upper half, find the median (Q3) of that portion. In this case, the upper half is:
11, 14, 17, 21, 23
Again, we have 5 data points in the upper half, so the median is the average of the 2nd and 3rd values:
Upper Median (Q3) = (17 + 21) / 2 = 19
5. Finally, subtract Q1 from Q3 to find the interquartile range:
Interquartile Range = Q3 - Q1 = 19 - 5.5 = 13.5
The answer is not given in the options provided. The correct answer is not listed.