A researcher conducted a survey of 6 teachers to determine how many times each teacher tutors students after school. The researcher recorded the findings in the table below.

​Teacher ​Number of Outcomes
1 ​18
2 ​ 15
3 ​12
4 ​23
5 ​ 15
6 ​ 19
Total ​100
What is the empirical probability that teacher #4 will tutor students after school?

I'd say 100%, since the teacher clearly tutors after school.

What you should have asked is what is the percentage of tutoring events were conducted by Teacher #4. That would be
23/100 = 23%

Ms. Poole, my PE teacher, asked the 100 seventh in my school if they could swim. Half the boys and two thirds of the girls said yes. Seventeen boys said no. How many seventh graders know how to swim?

To determine the empirical probability that teacher #4 will tutor students after school, we need to calculate the ratio of the number of times teacher #4 tutors to the total number of outcomes.

From the table, we can see that teacher #4 tutored students after school 23 times.

The total number of outcomes is 100.

Therefore, the empirical probability that teacher #4 will tutor students after school is:

23 (number of times teacher #4 tutors) / 100 (total number of outcomes) = 0.23

So, the empirical probability is 0.23 or 23%.

To find the empirical probability, also known as experimental probability, that teacher #4 will tutor students after school, we need to determine the number of outcomes favorable to the event (teacher #4 tutoring) and divide it by the total number of outcomes.

Looking at the given table, we can see that teacher #4 tutored students after school 23 times out of the total of 100 outcomes recorded.

So, the empirical probability that teacher #4 will tutor students after school is:

Number of outcomes favorable to the event (teacher #4 tutoring) = 23
Total number of outcomes = 100

Empirical probability = Number of outcomes favorable to the event / Total number of outcomes
= 23 / 100
= 0.23

Therefore, the empirical probability that teacher #4 will tutor students after school is 0.23 or 23%.