Calculate the linear expansivity (α) of brass of length 120m that assumes anew length of 120.05m, when heated through a temperature of 100 degree Celsius.
If it's linear, it looks like (120.05-120)m/100°C = 0.0005 m/°C
calculate the alpha of brass long 120m that assume a new length of 120.05cm when heated through a temperature 100°c
0.42 x 10^-5 k^-1
To calculate the linear expansivity (α) of brass, we can use the formula:
α = ΔL / (L0 * ΔT)
where:
α = linear expansivity
ΔL = change in length
L0 = initial length
ΔT = change in temperature
In this case, the change in length (ΔL) is the new length (120.05m) minus the initial length (120m), which is equal to 0.05m.
The initial length (L0) is given as 120m.
The change in temperature (ΔT) is the final temperature (100°C) minus the initial temperature (0°C), which is equal to 100°C.
Now, we can substitute these values into the formula:
α = 0.05m / (120m * 100°C)
Calculating this, we have:
α = 0.05m / (12000m * 100°C)
α = 0.05 / 12000 * 100
α ≈ 4.17 x 10^-5 per °C
Therefore, the linear expansivity (α) of brass is approximately 4.17 x 10^-5 per °C.