E bisects DF, DE = 2y, and EF = 8y-3. Find DE, EF, and DF.
since E bisects DF, DE=EF. So
2y = 8y-3
find y, and then you can get the lengths desired.
To find the lengths of DE, EF, and DF, we'll first start by understanding what it means for E to bisect DF. When a point bisects a line segment, it means that it divides the line segment into two equal parts. In this case, E divides DF into two equal parts, so DE is equal to EF.
Let's start by finding the length of DE:
Given: DE = 2y
Since E bisects DF, DE = EF, so EF = 2y.
Next, we need to find the length of EF:
Given: EF = 8y - 3
Lastly, we'll find the length of DF. Since E bisects DF, we know that the sum of DE and EF is equal to DF. So we can add DE and EF to find DF.
DF = DE + EF
= 2y + (8y - 3)
= 10y - 3
Therefore, the lengths of DE, EF, and DF are:
DE = 2y
EF = 8y - 3
DF = 10y - 3