A 5.00102-g block of metal absorbs 5016 J of heat when it's temperature changes from 20.0 degrees Celsius to 30.0 degrees Celsius. Calculate specific heat of the metal.
To calculate the specific heat of a material, we can use the equation:
Q = m * c * ΔT
Where:
Q is the amount of heat transferred
m is the mass of the material
c is the specific heat capacity of the material
ΔT is the change in temperature
In this case, we are given the following information:
Q = 5016 J
m = 5.00102 g (convert to kg by dividing by 1000)
ΔT = (30.0 - 20.0) degrees Celsius
First, let's convert the mass from grams to kilograms:
m = 5.00102 g / 1000 = 0.00500102 kg
Now, we can rearrange the equation to solve for c:
c = Q / (m * ΔT)
Substituting the given values:
c = 5016 J / (0.00500102 kg * (30.0 - 20.0) °C)
Simplifying the equation:
c = 5016 J / (0.00500102 kg * 10.0 °C)
c = 5016 J / 0.0500102 kg°C
c ≈ 1.001 J/(g°C)
So, the specific heat capacity of the metal is approximately 1.001 J/(g°C).
s.h. = heat / [mass * (temperature change)]
the answer has the same number of sig fig
... as the input with the fewest sig fig