a charge 5mc is placed at a point. What is the work required to carry 1C of charge once round it in a circle of radius 12cm
none. The force is perpendicular to the motion.
answer is 100
To calculate the work required to carry a charge around a circular path, we need to consider the electric potential difference (V) between the starting and ending points of the path and the charge (Q) being moved.
The electric potential difference is given by the equation:
V = k * Q / r
where:
- V is the electric potential difference
- k is Coulomb's constant (k = 9 × 10^9 Nm^2/C^2)
- Q is the charge being moved (1C in this case)
- r is the radius of the circular path (12cm = 0.12m in this case)
So, the electric potential difference can be calculated as:
V = (9 × 10^9 Nm^2/C^2) * (1C) / (0.12m)
V = 7.5 × 10^10 Nm/C
Now, to calculate the work (W), we can use the equation:
W = Q * V
W = (1C) * (7.5 × 10^10 Nm/C)
W = 7.5 × 10^10 Nm
Therefore, the work required to carry 1C of charge once around the circle of radius 12cm is 7.5 × 10^10 Nm.