A square has the following vertices. Find the area of the square.
(−7, −5), (−4, −2), (−4, −8), (−1, −5)
6√ square units
18√ square units
6 square units **
18 square units
check my work thx
It's not even a square.
https://www.wolframalpha.com/input/?i=plot+%7B%28%E2%88%927%2C+%E2%88%925%29%2C+%28%E2%88%924%2C+%E2%88%922%29%2C+%28%E2%88%924%2C+%E2%88%928%29%2C+%28%E2%88%921%2C+%E2%88%925%29%7D
The correct answer is the sqrt of 18 :)
its definately not a square ive been trying to figure this out for my daughter will talk to the teacher tomorrow and hopefully beback with an answer/sollution. i think it may be a typo. :)
To find the area of a square given its vertices, you can use the distance formula to find the length of one side of the square. Then, you can square this value to find the area.
Let's find the distance between two adjacent vertices: (-7, -5) and (-4, -2). Using the distance formula:
d = √[(x₂ - x₁)² + (y₂ - y₁)²]
Substituting the coordinates, we have:
d = √[(-4 - (-7))² + (-2 - (-5))²]
= √[(3)² + (3)²]
= √[9 + 9]
= √(18)
= 3√2
Now, we have found the length of one side of the square, which is 3√2. To find the area, we square this value:
Area = (3√2)²
= 9(2)
= 18
Therefore, the area of the square is 18 square units. It appears that your answer of 18 square units is correct. Well done!
I disagree with your answer.
Start by plotting the points on a piece of graph paper, then calculate the length of one side.
End points of one side: (-7, -5), (-1, -5).
A = L^2 = (-1+7)^2+(-5+5)^2 = 36 sq. units.