If leah is 6 years older than sue, John is 5 years older than Leah and the total age is 41, how old is sue
L = S + 6
J = L + 5 = S + 6 + 5
S + S + 6 + S + 6 + 5 = 41
sue is x yrs old.
Leah: x+6.
John: x+6 +5 = x+11.
x + x+6 + x+11 = 41
X = 8.
To find out Sue's age, let's breakdown the information given:
1. Let's assume Sue's age as "x" years.
2. Leah is 6 years older than Sue, so Leah's age is "x + 6" years.
3. John is 5 years older than Leah, so John's age is "(x + 6) + 5" years.
4. The total age of Sue, Leah, and John is 41 years, so:
x + (x + 6) + [(x + 6) + 5] = 41
Now, let's solve this equation for x:
2x + 17 = 41
2x = 41 - 17
2x = 24
x = 24 / 2
x = 12
Therefore, Sue is 12 years old.