2/3 of the doughnuts in a box have frosting. 1/2 of the doughnuts with frosting have sprinkles. What fraction of the doughnuts in the box have frosting and sprinkles?
1/3
Junior's brother is 1\dfrac121
2
1
1, start fraction, 1, divided by, 2, end fraction meters tall. Junior is 1\dfrac151
5
1
1, start fraction, 1, divided by, 5, end fraction of his brother's height.
How tall is Junior?
Answer: 1/3 of the donuts
To find the fraction of the doughnuts in the box that have frosting and sprinkles, we can begin by finding the fraction of doughnuts with frosting. Given that 2/3 of the doughnuts have frosting, we can say that out of every 3 doughnuts, 2 have frosting.
Next, we need to find the fraction of doughnuts with frosting that also have sprinkles. We are told that 1/2 of the doughnuts with frosting have sprinkles. So out of every 2 doughnuts with frosting, 1 has sprinkles.
To find the fraction of doughnuts that have both frosting and sprinkles, we need to multiply these two fractions together. Multiplying 2/3 by 1/2, we get:
(2/3) * (1/2) = 2/6 = 1/3
Therefore, 1/3 of the doughnuts in the box have both frosting and sprinkles.
If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
Right!