If a gas occupies a volume of 400cm3 at S.T.P. At what temperature will the gas occupies a
volume of 850cm3and have a pressure of 720mmHg?
Use (P1V1/T1) = (P2V2/T2)
Remember STP is 273.14 Kelvin and 760 mm Hg pressure. Post your work if you want someone to check it.
To find the temperature at which the gas occupies a volume of 850 cm3 and has a pressure of 720 mmHg, we can use the combined gas law equation:
(P1 × V1) / T1 = (P2 × V2) / T2
Where:
P1 = Pressure at the initial state (S.T.P.) = 760 mmHg
V1 = Volume at the initial state (S.T.P.) = 400 cm3
T1 = Temperature at the initial state (S.T.P.) = 273 K (0 degrees Celsius)
P2 = Pressure at the final state = 720 mmHg
V2 = Volume at the final state = 850 cm3
T2 = Temperature at the final state (which we need to find)
Now, we can rearrange the equation to solve for T2:
T2 = (P2 × V2 × T1) / (P1 × V1)
Substituting the given values:
T2 = (720 mmHg × 850 cm3 × 273 K) / (760 mmHg × 400 cm3)
Simplifying the equation:
T2 = (550800 K · cm3 · mmHg) / ( 304000 K · cm3)
Canceling out the units:
T2 = 1.81 K
Therefore, the temperature at which the gas occupies a volume of 850 cm3 and has a pressure of 720 mmHg is approximately 1.81 Kelvin.