Ab = 125ft
Bc = 85ft
C = 63°
1. Find the length of Ac
2. Whats the total length around triangle if there is two 3ft opening ?
1. Use the law of sines to find angle A
sinA/85 = sin63°/125
Now find AC using angle B (180-63-A) and
the law of sines: AC/sinB = sin63°/125
or the law of cosines: AC^2 = 125^2 + 85^2 - 2(125)(85) cosB
2. add up the three sides and subtract 2*3