In a primary school 70% of the boys and 55% of the girls can ride a bicycle .if a boy and a girl are chosen at random what is the probability that both of them can ride a bicycle.that neither of them can ride a bicycle.
let B1 represent boy can ride bike
let B0 represent boy can't ride bike, same for G1 and G0
B1 G1-->.7*.55 = .385
B1 G0--> .7*.45 = .315
B0 G1--> .3*.55 = .165
B0 G0--> .3*.45 = .135
Take your pick, notice that the cases add to 1, as it should
In a primary school 70% percent of the boys and 5% percent of girls can ride byeclar if a boy and a girl is choose at random what is the probability that both of them can ride bike that neither of them can ride bike
To calculate the probability of both a boy and a girl being able to ride a bicycle, we need to multiply the individual probabilities together.
Let's assume that there are 100 boys and 100 girls in the primary school for simplicity.
Out of the 100 boys, 70% can ride a bicycle, which means 70 boys can ride. Similarly, out of the 100 girls, 55% can ride a bicycle, which means 55 girls can ride.
The probability of choosing a boy who can ride a bicycle is 70/100 = 0.7, and the probability of choosing a girl who can ride a bicycle is 55/100 = 0.55.
To find the probability of both a boy and a girl being able to ride, we multiply these probabilities together:
0.7 x 0.55 = 0.385
So, the probability that both a boy and a girl chosen at random can ride a bicycle is 0.385, or 38.5%.
To calculate the probability that neither of them can ride a bicycle, we need to find the complement of the probability that both can ride. In other words, it is the probability that at least one of them cannot ride.
The probability of at least one of them not being able to ride is 1 - 0.385 = 0.615.
So, the probability that neither of them can ride a bicycle is 0.615, or 61.5%.