What is the 20th term in the sequence defined by tn = n^2 - 2n/2n - 30?
I assume you meant:
t(n) = (n^2 - 2n)/(2n - 30)
just replace n with 20 and do the arithmetic
let me know what your answer.
36?
To find the 20th term in the sequence defined by tn = (n^2 - 2n) / (2n - 30), we need to substitute n = 20 into the formula.
t20 = (20^2 - 2(20)) / (2(20) - 30)
= (400 - 40) / (40 - 30)
= 360 / 10
= 36
Therefore, the 20th term in the sequence is 36.
To find the 20th term in the sequence defined by tn = n^2 - 2n/2n - 30, we can substitute n = 20 into the formula.
First, let's substitute n = 20 into the formula:
t20 = (20^2 - 2(20))/(2(20) - 30)
= (400 - 40)/(40 - 30)
= (360)/(10)
= 36
Therefore, the 20th term in the sequence defined by tn = n^2 - 2n/2n - 30 is 36.