if sin p = 3/5 and p is an acute angle, what is the value of tan p.

trigonometry

Given that tan x = 5/12, what is the value of sin x + cos x?

draw a triangle with opposite leg=3 and hypotenuse=5

tan p = opposite/adjacent = 3/4

similarly, in a 5-12-13 right triangle
sinx + cosx = 5/13 + 12/13

timilehin oyewole

my name I'd Oyewole timilehin

The answer is 4

I can't find

Tank=8/12

5-12-13
=5/13+12/13

To find the value of tan p, we can use the relationship between sine, cosine, and tangent in a right triangle. Let's start by drawing a right triangle.

Step 1: Draw a right triangle.

-
|\
| \
p | \
| \
|____\
x

In our triangle, the angle p is an acute angle, so it is one of the non-right angles. The side opposite to angle p is represented as "x."

Step 2: Label the sides of the triangle.

We are given that sin p = 3/5, which tells us that the ratio of the side opposite angle p to the hypotenuse is 3/5.

We can use Pythagoras' theorem to find the remaining side. Since we have the opposite side ("x") and the hypotenuse, we can find the adjacent side.

Step 3: Use Pythagoras' theorem to find the length of the adjacent side.

According to Pythagoras' theorem:

(Adjacent Side)^2 = (Hypotenuse)^2 - (Opposite Side)^2

Let's substitute the known values into the equation:

(Adjacent Side)^2 = (5)^2 - (3)^2
(Adjacent Side)^2 = 25 - 9
(Adjacent Side)^2 = 16
Adjacent Side = 4

Now we have the lengths of both the opposite side (3) and the adjacent side (4).

Step 4: Find the value of tan p.

Tan p is equal to the ratio of the opposite side to the adjacent side in a right triangle.

Tan p = Opposite Side/Adjacent Side
Tan p = 3/4

Therefore, the value of tan p is 3/4.