What mass of Ca(OH)2 is required to prepare 200mL of 0.2N solution?
I get 0.1 for Molarity.
N=Molarity*Equivalent
Equivalent=2 because you have two OH groups.
N=0.2
Molarity=0.1
0.2L*0.1M=moles
Moles*(molecular weight)=mass needed in grams
See your last post. M = 2 x N for Ca(OH)2.
Mols =M x L
g = mols x molar mass
Post your work if you get stuck.
To calculate the mass of Ca(OH)2 required to prepare a 0.2N solution, we need to follow these steps:
Step 1: Calculate the molar mass of Ca(OH)2.
The molar mass is the sum of the atomic masses of each element in the compound.
The atomic masses are as follows:
Ca = 40.08 g/mol
O = 16.00 g/mol
H = 1.01 g/mol
Total molar mass of Ca(OH)2 = (Ca * 1) + (O * 2) + (H * 2)
= (40.08 * 1) + (16.00 * 2) + (1.01 * 2)
= 40.08 + 32.00 + 2.02
= 74.10 g/mol
Step 2: Calculate the number of moles of Ca(OH)2 required.
To calculate the moles, we use the formula:
Moles = Normality * Volume (in liters)
Convert the volume given in mL to liters: 200 mL = 0.2 L
Moles = 0.2N * 0.2 L
= 0.04 moles
Step 3: Calculate the mass of Ca(OH)2 required.
To calculate the mass, we use the formula:
Mass = Moles * Molar mass
Mass = 0.04 moles * 74.10 g/mol
= 2.964 g
Therefore, to prepare 200 mL of a 0.2N solution of Ca(OH)2, you would need approximately 2.964 grams of Ca(OH)2.
To determine the mass of Ca(OH)2 required to prepare a 0.2N solution, we need to know the molar mass of Ca(OH)2 and the volume of the solution.
The molar mass is calculated by summing the atomic masses of all the individual atoms in the compound. For Ca(OH)2:
- The atomic mass of calcium (Ca) is 40.08 g/mol.
- The atomic mass of oxygen (O) is 16.00 g/mol.
- The atomic mass of hydrogen (H) is 1.01 g/mol.
Since there are two oxygen atoms and two hydrogen atoms in Ca(OH)2, we multiply their atomic masses by 2:
2 * 16.00 g/mol = 32.00 g/mol (for oxygen)
2 * 1.01 g/mol = 2.02 g/mol (for hydrogen)
So, the molar mass of Ca(OH)2 is:
40.08 g/mol (for calcium) + 32.00 g/mol (for oxygen) + 2.02 g/mol (for hydrogen) = 74.10 g/mol.
Now, to calculate the mass of Ca(OH)2 required:
First, we need to find the number of moles of Ca(OH)2 using the formula:
moles = concentration (N) * volume (L)
Here, the concentration is given as 0.2N and the volume is 200 mL. However, we need to convert the volume from milliliters (mL) to liters (L):
200 mL = 200/1000 L = 0.2 L
Using the formula:
moles = 0.2N * 0.2 L = 0.04 mol
Finally, to find the mass, we use the formula:
mass = moles * molar mass
mass = 0.04 mol * 74.10 g/mol = 2.964 g
Therefore, approximately 2.964 grams of Ca(OH)2 is required to prepare 200 mL of 0.2N solution.