A wire of length 100cm and cross-sectional area of 2.0 x 10-3cm2 has a resistance of 0.10 Ω. Calculate its electrical conductivity.?
P = RA/L = 0.1*(2*10^-3)/(1*10^2) = 2*10^-6 ohm*cm. = resistivity.
Conductivity = 1/P =
conductivity = 1/P siemens/meter.
if you know the definition of conductivity, and watch the units, the answer should be clear.
To calculate the electrical conductivity of a wire, we can use the formula:
Electrical Conductivity (σ) = (1 / Resistance) x (Area / Length)
Given:
Length (L) = 100 cm = 1 meter (since 1 meter = 100 cm)
Cross-sectional Area (A) = 2.0 x 10^(-3) cm^2 = 2.0 x 10^(-5) m^2 (since 1 m^2 = 10,000 cm^2)
Resistance (R) = 0.10 Ω
Substituting these values into the formula, we get:
σ = (1 / 0.10 Ω) x (2.0 x 10^(-5) m^2 / 1 m)
simplifying:
σ = 10 Ω^(-1) x 2.0 x 10^(-5) m
σ = 2.0 x 10^(-4) Ω^(-1) m^(-1)
Therefore, the electrical conductivity of the wire is 2.0 x 10^(-4) Ω^(-1) m^(-1).