Prepare 100ml of 2.50M HCl solution for tomorrow's undergraduate experiment. The Stock Solutions cabinet is under the Stockroom Explorer. You will find a 2.50 liter bottle containing 11.6M HCl. Please prepare a flask containing 100ml of a 2.50M solution. To ensure proper credit, please write your calculations in the space given below. Screen capture your solution.

You have an 11.6 M HCl solution and you want to use that to prepare 100 mL of 2.50 M HCl solution. You can go about this several ways but here are two of them. The first is to use the dilution formula of mL1 x M1 = mL2 x M2

mL1 x 11.6 = 100 x 2.50
mL1 = 100 x 2.50/11.6 = 21.55.
So you place 21.55 mL of the 11.6 M HCl stock solution into a 100 mL volumetric flask, add distilled or deionized water up to the mark on the volumetric flask, mix thoroughly, stopper and label.
The second is to ask yourself how many moles is in the final solution? That is M x L = 2.50 M x 0.100 L = 0.250 mols.
Then how many L of the 11.6 M HCl stock solution will get 0.250 mols. That is M = mols/L
11.6 = 0.250/L and L = 0.250/11.6 = 0.02155 L oe 21.55 mL.

could you please help me with this problem

Thank you.

To prepare 100ml of a 2.50M HCl solution, we will use the formula:

M1V1 = M2V2

Where:
M1 = concentration of the stock solution
V1 = volume of the stock solution
M2 = concentration of the desired solution
V2 = volume of the desired solution

In this case:
M1 = 11.6M (concentration of the stock solution)
V1 = ?
M2 = 2.50M (concentration of the desired solution)
V2 = 100ml (volume of the desired solution)

Rearranging the formula, we have:

V1 = (M2 * V2) / M1

Substituting the values:
V1 = (2.50M * 100ml) / 11.6M

Calculating, we have:

V1 = 21.55ml

Therefore, to prepare 100ml of a 2.50M HCl solution, we will measure 21.55ml of the 11.6M HCl stock solution and dilute it with water to a final volume of 100ml.

To prepare a 100ml of 2.50M HCl solution, we will need to dilute the stock solution.

The given stock solution has a concentration of 11.6M HCl, and we want to prepare a 2.50M solution.

To calculate the volume of the stock solution needed, we can use the equation:

C1V1 = C2V2

Where:
C1 = concentration of stock solution (11.6M)
V1 = volume of stock solution needed
C2 = desired concentration (2.50M)
V2 = desired volume (100ml)

Rearranging the equation to solve for V1:

V1 = (C2 * V2) / C1

Plugging in the values:

V1 = (2.50M * 100ml) / 11.6M

V1 = 21.55 ml (rounded to two decimal places)

Therefore, we need to measure 21.55ml of the stock solution and add it to a flask, then add distilled water to reach a total volume of 100ml.

Please note that it is important to accurately measure volumes and use appropriate precautions when handling concentrated acids.