Maria shares some seashells with Jeff. Maria says, “Two for you, three for me, two for you, three for me ...” Tonya watches. At the end, she says, “So Jeff got 2/3 of the shells.” Do you agree with Tonya? Give reasons for your answer.
nope.
2 for Jeff
3 for Maria
so, Jeff got 2/5 of the shells, not 2/3.
This illustrates the difference between probability (2/5) and odds (2:3)
how is it 2/5 of shells tho?
No, I disagree with Tonya because..
2 shells for Jeff.
3 shells for Maria.
Add 2+3 which gives 5.
So It's 2/5 not 2/3.
I'm pretty sure this is the answer. ;-;
To determine whether Tonya's statement is correct or not, we need to analyze the situation and the distribution of seashells between Maria and Jeff.
According to Maria, the distribution pattern is "Two for you, three for me" repeated multiple times. Let's break down this pattern:
- First, Maria gives Jeff 2 seashells.
- Then, Maria keeps 3 seashells for herself.
- Again, Maria gives Jeff 2 seashells.
- Maria keeps another 3 seashells for herself.
Based on this pattern, we can observe that Maria is giving Jeff 2 seashells every time, while keeping 3 for herself. Therefore, Jeff receives an equal number of seashells after every round of distribution.
Now, let's determine the overall share of seashells between Maria and Jeff by considering the distribution pattern. Assume Maria starts with 'm' seashells, and Jeff starts with 'j' seashells.
After the first iteration:
- Maria gives Jeff 2 shells, so she has (m - 2) shells left.
- Jeff receives 2 shells, so he has (j + 2) shells.
After the second iteration:
- Maria gives Jeff 2 shells again, so she has [(m - 2) - 2] shells left, which simplifies to (m - 4) shells.
- Jeff receives 2 shells, so he has [(j + 2) + 2] shells, which simplifies to (j + 4) shells.
As we can see, for every round of distribution, Maria's seashell count decreases by 4 shells, while Jeff's count increases by 4 shells. Therefore, the ratio of their shell counts remains constant:
Maria's shells to Jeff's shells = (m - 2) : (j + 2)
After the second round, this ratio is (m - 4) : (j + 4)
Since there is no mention of any additional rounds of distribution, we cannot accurately determine the final shell counts of Maria and Jeff. Therefore, we cannot say whether Jeff got exactly 2/3 of the shells or not.
In conclusion, without more information about the total number of seashells initially held by Maria and Jeff, we cannot agree or disagree with Tonya's statement that "Jeff got 2/3 of the shells."