A girl walks 800m on a bearing of 129°
calculate how far east and west she is from her starting piont.
All angles are measured CW from +y-axis.
D = 800m[129o].
D = 800*sin129+(800*cos129)i = 622 - 503i.
622 meters East and 503 meters South.
800 cos39°
you decide whether that's east or west. It won't be both...
65.2cm
To calculate how far east and west the girl is from her starting point, we need to break down the distance traveled into eastward and westward components.
First, let's find the eastward component of the distance:
To do this, we need to find the eastward (x) component of the displacement using trigonometry. The formula for finding a component of a vector given the magnitude and the angle is:
x component = magnitude * cos(angle)
In this case, the magnitude is 800m, and the angle is 129°.
Plugging these values into the formula, we get:
x component = 800m * cos(129°)
Using a calculator, we find that the eastward component is approximately -289.16m (negative because it is eastward).
Next, let's find the westward component of the distance:
Since the girl is traveling eastward, the westward component will be the negation of the eastward component.
Therefore, the westward component is approximately +289.16m.
So, the girl is approximately 289.16m east and 289.16m west of her starting point.