The digit in lakh place is twice the digit in the thousand place and it is a product of 4 table
Twas bryllyg, and the slythy toves
Did gyre and gymble in the wabe:
All mimsy were the borogoves;
And the mome raths outgrabe.
Well, that's quite a lot of math to chew on! Let's break it down, shall we? If the digit in the lakh (100,000s) place is twice the digit in the thousand (1,000s) place, we have a pretty interesting relationship going on.
Now, let's factor in the "product of 4 table" bit. If the digit in the lakh place is indeed a product of the 4 table, we can try to figure it out.
Let's start with the basic 4 times table:
4 x 1 = 4
4 x 2 = 8
4 x 3 = 12
4 x 4 = 16
...and so on.
Now, we want to find a number that also doubles the digit in the thousand place. So, let's see if we can find a match, shall we?
2 x 4 = 8! Bingo! We have a match! So, if the digit in the thousand place is 4, then the digit in the lakh place is 8.
So, to sum it up: The digit in the lakh place is twice the digit in the thousand place (8 is indeed twice 4), and it is a product of the 4 table!
Now, wasn't that a fun little math puzzle? Keep those brain cells working!
Let's break down the given information step by step:
Step 1: The digit in the lakh place is twice the digit in the thousand place.
Let's represent the digit in the lakh place as A and the digit in the thousand place as B. According to the given information, A = 2B.
Step 2: The digit in the lakh place is a product of 4 tables.
We know that the digit in the lakh place, which is A, is a product of the 4 table. In other words, A is a multiple of 4.
From step 1, we have A = 2B. So, we can rewrite step 2 as 2B is a multiple of 4.
Step 3: Simplify the condition from step 2.
For 2B to be a multiple of 4, B must be an even number because multiplying an even number by 2 always gives an even number, and multiples of 4 are even numbers.
Therefore, the digit in the thousand place, which is B, must be an even number.
To summarize,
The digit in the lakh place is twice the digit in the thousand place (A = 2B), and the digit in the lakh place is a product of the 4 table (A is a multiple of 4). The digit in the thousand place, B, must be an even number.
To find the digit in the lakh place, we need to divide the given number by 10,000 (since the digit in the thousand place is four decimal places to the right of the digit in the lakh place).
Let's represent the digit in the thousand place as 'x'.
We know that the digit in the lakh place is twice the digit in the thousand place. So, the digit in the lakh place can be represented as '2x'.
We are also given that the digit in the lakh place is a product of the 4 table. This means '2x' must be a multiple of 4. In other words, '2x' must be divisible by 4.
To check if '2x' is divisible by 4, we need to check if 'x' is divisible by 2.
Now let's go through the multiplication table of 4 and find the value of 'x' that satisfies the given conditions.
- Multiplication table of 4:
4 * 1 = 4
4 * 2 = 8
4 * 3 = 12
4 * 4 = 16
4 * 5 = 20
4 * 6 = 24
4 * 7 = 28
4 * 8 = 32
4 * 9 = 36
4 * 10 = 40
From the multiplication table of 4, we can see that 'x' can only be either 2, 6, or 8, as these are the values that produce a multiple of 4 when multiplied by 2.
Therefore, the digit in the lakh place can be 4, 12, or 16 depending on the value of 'x'.