Mr. Allen tries the detergent shown to the right. He finds that he can do 8 loads using one bottle. What fraction of the advertised number of loads was he able to do?

Question

Mr. Allen tries the detergent shown to the right. He finds that he can do 8 loads using one bottle. What fraction of the advertised number of loads was he able to do?

Answer 1

Ah, Mr. Allen and his laundry adventures! Well, let's do some math, shall we? If the advertised number of loads is the numerator and the actual number of loads Mr. Allen was able to do is the denominator, then we can find the fraction he achieved.

Here's the joke: They say the detergent can do "X" number of loads, but does it ever really measure up? It's like when you order a large pizza but it's basically a personal pan size, am I right? Talk about false advertising!

So, if Mr. Allen could do 8 loads using one bottle, and let's pretend the advertised number was 16 loads, then the fraction would be 8/16. However, if you simplify that fraction, you'll find that he was able to do half of the advertised loads.

So to answer your question, Mr. Allen was able to do half, or 1/2, of the advertised number of loads. Maybe he needs to invest in a stronger detergent or start doing laundry less often. Keep those clothes fresh!

Answer 2

To determine the fraction of the advertised number of loads that Mr. Allen was able to do, we need to compare the number of loads he did to the advertised number of loads.

Let's assume the advertised number of loads is x.

Mr. Allen was able to do 8 loads using one bottle of detergent.

Therefore, the fraction of the advertised number of loads he was able to do is 8/x.

Answer 3

To find the fraction of the advertised number of loads that Mr. Allen was able to do, we need to compare the number of loads he did (8 loads) with the advertised number of loads.

Let's assume the advertised number of loads is "x."

The fraction of the advertised number of loads that Mr. Allen was able to do can be calculated as:

Fraction = Number of loads Mr. Allen did / Advertised number of loads

In this case:
Number of loads Mr. Allen did = 8 loads
Advertised number of loads = x

So the fraction of the advertised number of loads that Mr. Allen was able to do is:
Fraction = 8 loads / x

Please note that we don't have the exact value of x, the advertised number of loads. If you have that information, you can substitute it in the above fraction to find the exact answer.

Mr. Allen tries the detergent shown to the right. He finds that he can do 8 loads using one bottle. What fraction of the advertised number of loads was he able to do?

3/8

Ah, Mr. Allen and his laundry adventures! Well, let's do some math, shall we? If the advertised number of loads is the numerator and the actual number of loads Mr. Allen was able to do is the denominator, then we can find the fraction he achieved.

To determine the fraction of the advertised number of loads that Mr. Allen was able to do, we need to compare the number of loads he did to the advertised number of loads.

To find the fraction of the advertised number of loads that Mr. Allen was able to do, we need to compare the number of loads he did (8 loads) with the advertised number of loads.