I need help with this question: x^2-20x+24
x =(20-√496)/2=10-2√ 31 = -1.136
x =(20+√496)/2=10+2√ 31 = 21.136
Either I am not that good with Algebra but I hope this helps
I hope Joseph waits for a real math tutor.
sorry, it's ±√(b^2-4ac)
you did ±√(b^2+4ac)
The given expression is x^2 - 20x + 24. It seems to be a quadratic trinomial, which means it follows the form ax^2 + bx + c.
To factor this quadratic trinomial, we need to find two numbers that multiply to give us the constant term (c = 24) and add up to the coefficient of the middle term (b = -20).
In this case, the two numbers that meet these conditions are -2 and -12. If we multiply -2 and -12, we get 24, and if we add -2 and -12, we get -20.
So, we can rewrite the expression as:
x^2 - 2x - 12x + 24
Now, we can group the terms together and then factor by grouping:
(x^2 - 2x) + (-12x + 24)
Taking out the common factors from each group, we get:
x(x - 2) - 12(x - 2)
Now, notice that we have a common binomial factor, (x - 2). We can factor that out:
(x - 2)(x - 12)
Therefore, the factored form of the expression x^2 - 20x + 24 is (x - 2)(x - 12).