If the third term of ap is 4 and ninth term of ap is -8 then which term of ap is zero
a+2d=4
a+8d=-8
6d=-12
d=-2
a=4-2d
a=4+4
a=8
a+(n-1)d=0
8-2(n-1)=0
4-(n-1)=0
-(n-1)=-4
n=5
a+8d=-8
6d=-12
d=-2
a=4-2d
a=4+4
a=8
a+(n-1)d=0
8-2(n-1)=0
4-(n-1)=0
-(n-1)=-4
n=5