A 1.0 kg rock is thrown straight upward with an initial speed of 8.0 m/s. What is its speed when it reaches a height of 1.6 m?
1/2 m v1^2 = m g h + 1/2 m v2^2
v1^2 - 2 g h = v2^2
8.0^2 - (2 * 9.8 * 1.6) = v2^2
v1^2 - 2 g h = v2^2
8.0^2 - (2 * 9.8 * 1.6) = v2^2