If the concentration of some reactant, B, is tripled, the rate of reaction triples. What is the order of B?
Wouldn't that be order 1.
rate = y = k*(B)^x where x is the order.
if rate is 3y when (B) = 3(B), what must be the value for x? 1, right?
if its tripled and factors increases by 9 the order must be 2 because 3^2 is 9. 3^1 would simply produce 3. That is why it is first order.
To determine the order of a reactant in a chemical reaction, you need to examine how changes in its concentration affect the rate of the reaction. In this case, the concentration of reactant B is tripled, and as a result, the rate of reaction also triples.
This information suggests that the rate of the reaction is directly proportional to the concentration of B raised to some power. Let's denote the order of reactant B as "n". Therefore, we can write the relationship between the rate of reaction (R) and the concentration of B ([B]) as:
R ∝ [B]^n
Based on the given information, we can express this relationship as:
3R = (3[B])^n
Since tripling the concentration of B leads to tripling the rate of reaction, we have:
(3[B])^n = 3[B]
To simplify this equation, we can cancel out the common factor of 3:
(3[B])^(n-1) = 1
Since any number raised to the power of 0 is equal to 1, we can conclude that:
n - 1 = 0
n = 1
Therefore, the order of reactant B in this reaction is 1.