How many (a) H+ ions and (b) OH" ions are present in 250 ml of a

solution of pH3?

14=pH+pOH

14-pH=pOH

H^+=10^-(pH)

OH^-=10^-(pOH)

You should get 1.0 x 10^-3 M and 1.0 x 10^-11 M. You can figure out which is which.