Solve
7^x = (7^(2x))/(7^4)
I'm not sure if I'm writing this correctly though, the second part of it is:
7 with a small 2x attached to it, OVER 7 with a small 4 (obviously to the power of)
7^x = 7^(2x)/(7^4)
7^x = 7^(2x-4)
x = 2x-4
x = 4
7^x = (7^(2x))/(7^4)
I'm not sure if I'm writing this correctly though, the second part of it is:
7 with a small 2x attached to it, OVER 7 with a small 4 (obviously to the power of)
7^x = 7^(2x-4)
x = 2x-4
x = 4