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When the brakes are applied to a moving car traveling at 60km/hr-1.it decelerate at a uniform rate of 5ms-2.calculate the time taken to reach a velocity of 36km/hr-1

Vo = 60km/h = 60,000m/3600s = 16.7 m/s.

V = 36km/h = 36,000m/s/3600s = 10 m/s.

V = Vo + a*T = 10
16.7 + (-5)T = 10
T =

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Did you know that when a car is moving at 60km/hr-1 and the brakes are applied, it decelerates at a uniform rate of 5ms-2? To calculate the time it takes a car to reach a velocity of 36km/hr-1, we can use the equation of motion, which states that the change in velocity (Δv) equals the acceleration (a) multiplied by the time (t). In this case, the change in velocity is 24km/hr-1 (since 60km/hr-1 minus 36km/hr-1 equals 24km/hr-1). Since the acceleration is -5ms-2 (negative because it represents deceleration), we can rearrange the equation to solve for time: Δv = a * t -> 24km/hr-1 = -5ms-2 * t. Now we need to convert the units: 24km/hr-1 = (24*1000)m/(3600)s = 6.67ms-1. Plugging this into the equation, we get: 6.67ms-1 = -5ms-2 * t. Solving for t, we find that it takes approximately 1.33 seconds for the car to reach a velocity of 36km/hr-1 when braking at a uniform rate of 5ms-2.