Trapezoid ABCD is formed by
A(–7,3), B(–5,6), C(0,6), and D(0,3).
Determine the length of the diagonal AC in trapezoid ABCD. Round to the nearest tenth and show all of your work.
Please help me!
;-;
whats the answer
12?
To determine the length of the diagonal AC in trapezoid ABCD, you can use the distance formula. The distance formula states that the distance between two points (x1, y1) and (x2, y2) is given by the formula:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
So, let's apply this formula to the given coordinates of points A and C:
The coordinates of point A are (-7, 3), and the coordinates of point C are (0, 6).
Using the distance formula, we can calculate the distance AC as follows:
d = sqrt((0 - (-7))^2 + (6 - 3)^2)
= sqrt((7)^2 + (3)^2)
= sqrt(49 + 9)
= sqrt(58)
≈ 7.6 (rounded to the nearest tenth)
Therefore, the length of the diagonal AC in trapezoid ABCD is approximately 7.6 units.
You are given both A and C.
So the length of AC = √( 0-(-5))^2 + (3-6)^2 )
AC = ...
your turn
Sorry I had a typo , used the wrong point
AC = √( 0-(-7))^2 + (6-3)^2 )
= √(49 + 9) = √58
no way to get 12, either way