A block experiences three forces acting on it: Force 1 of 10N south, Force 2of 10N East, Force 3 of 5N North. The block moves 2 meters west. Which did most work?
work done is force times distance IN THE DIRECTION OF the force.
It moved West
force1 did nothing
force 3 did nothing
Force 2 was EAST but the block moved WEST so it did NEGATIVE work on the block (slowed it down) -10 N * 2 m = -20 Nm = -20 Joules
Fr = -10i + 10 + 5i = 10 - 5i
= 11.2N.[-26.6o] = 11.2N.[333o] CCW = 63o E.of S. = Resultant force.
Based on the resultant force, it is not possible for the block to move west.
Do you mean 2 meters East?
It was already moving :)
To determine which force did the most work, we need to calculate the work done by each force.
The work done by a force can be calculated using the formula: W = F * d * cos(theta), where W is the work done, F is the magnitude of the force, d is the displacement caused by the force, and theta is the angle between the force and the direction of displacement.
Let's calculate the work done by each force:
1. Force 1 (10N south): The block moves 2 meters west, so the displacement caused by Force 1 is in the opposite direction. The angle between Force 1 and the displacement is 180 degrees (since they are opposite directions). Therefore, the work done by Force 1 is: W1 = 10N * 2m * cos(180°).
2. Force 2 (10N east): The block moves 2 meters west, so the displacement caused by Force 2 is in the opposite direction. The angle between Force 2 and the displacement is also 180 degrees. Therefore, the work done by Force 2 is: W2 = 10N * 2m * cos(180°).
3. Force 3 (5N north): Since Force 3 is acting in a perpendicular direction to the displacement, its work done will be zero. The angle between Force 3 and the displacement is 90 degrees, so cos(90°) = 0.
Now, let's calculate the values:
W1 = 10N * 2m * cos(180°)
W2 = 10N * 2m * cos(180°)
W3 = 5N * 2m * cos(90°) = 0
As we can see, the work done by both Force 1 and Force 2 is the same. They both have a magnitude of 20 Joules.
Therefore, in this scenario, both Force 1 and Force 2 did the most work, with a magnitude of 20 Joules each.