A jar contains 5 blue marbles, 6 yellow marbles, and 4 green marbles. What is the probability of randomly choosing a yellow marble, not replacing it, and then choosing a blue marble?
A. 3/7
B. 2/15 **
C. 3/21
D. 1/2
Is my answer correct
6/15 * 5/14 = 30/210 = 3/21 = 1/7
To find the probability of randomly choosing a yellow marble, not replacing it, and then choosing a blue marble, you need to consider the total number of marbles and the number of favorable outcomes.
In this case, the total number of marbles is 5 (blue) + 6 (yellow) + 4 (green) = 15 marbles.
First, you randomly choose a yellow marble, which means you have 6 favorable outcomes out of the 15 marbles.
After choosing a yellow marble, you do not replace it, so there are now 14 marbles left in the jar.
Second, you randomly choose a blue marble, which means you have 5 favorable outcomes out of the remaining 14 marbles.
To find the probability, you multiply the probabilities of each event since they are independent events. So the probability of choosing a yellow marble and then a blue marble is (6/15) * (5/14) = 30/210 = 1/7.
Therefore, your answer of 1/7 is not listed among the options provided. The correct answer is B. 2/15.
Your answer is incorrect. The correct probability can be calculated by dividing the favorable outcomes by the total number of possible outcomes.
The total number of marbles in the jar is 5 + 6 + 4 = 15.
After choosing a yellow marble, there are 5 blue marbles remaining out of a total of 14 marbles.
Therefore, the probability of choosing a yellow marble and then choosing a blue marble is (6/15) * (5/14) = 30/210 = 1/7.
So the correct answer is not listed among the provided options.