Ca(NO 3 ) 2 + Na 2 CO 3 �� CaCO 3 + 2NaNO 3
net ionic equation?
Ca(NO3)2 + Na2CO3 ==> CaCO3 + 2NaNO3
The above is the full balanced molecular equation. Convert to the balanced full ionic equation next like this.
Ca^2+ + 2NO3^- + 2Na^+ + [CO3]^2- ==> CaCO3 + 2Na^+ + 2NO3^-
Next you cancel those ions that occur on BOTH sides of the equation. I see 2NO3^- on both sides. Cancel those. What's left is the net ionic equation.
To find the net ionic equation, we need to first write the balanced molecular equation for the reaction, which in this case is:
Ca(NO3)2 + Na2CO3 -> CaCO3 + 2NaNO3
Next, we need to identify the soluble compounds and break them down into their ions. In this reaction, all the compounds are soluble except for CaCO3, which is insoluble. Breaking down the soluble compounds, we have:
Ca(NO3)2 (aq) -> Ca2+ (aq) + 2NO3- (aq)
Na2CO3 (aq) -> 2Na+ (aq) + CO3^2- (aq)
Now, we can cancel out the spectator ions, which are the ions that appear on both sides of the equation. In this case, the spectator ions are Ca2+ and 2NO3-. We are left with:
Ca2+ (aq) + CO3^2- (aq) -> CaCO3 (s) + 2Na+ (aq)
Finally, we can write the net ionic equation by eliminating the spectator ions that don't participate in the reaction. The net ionic equation for this reaction is:
CO3^2- (aq) + Ca2+ (aq) -> CaCO3 (s)
So, the net ionic equation for the given reaction is CO3^2- (aq) + Ca2+ (aq) -> CaCO3 (s).