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chemistry

Iron (iii) hydroxide reacts with acetic acid to form iron (iii) acetate and water. If 45.4 grams of water are formed, how many grams of iron (iii) acetate will be produced?

Fe(OH)3 + 3HC2H2O2 --> Fe(C2H3O2)3 + 3H2O

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  1. Fe(OH)3 + 3HC2H2O2 --> Fe(C2H3O2)3 + 3H2O
    How many mols in 45.4 g H2O. mols = g/molar mass
    = 45.4/18 = 2.5 but that's an estimate. You should redo all of these calculations. Now use the coefficients in the equation.
    Then 2.5 mols H2O x ( 1 mol Fe(C2H3O2)3/3 mols H2O) = mols Fe(C2H3O2)3.
    Convert that to grams with the above formula.

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    DrBob222

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