I have a lot of these problems please can someone explain to how to do them . I seen the teacher notes i still dont see it .
April has the fewest
Jasmine has 7 more than April
Laura has twice as many as jasmine
Liam has 3 times as many as April
Julia has 6 fewer than jasmine
Write algebraic equations to find out how many each has ?
more than x: x+?
less/fewer than x: x-?
Julia has 6 fewer than jasmine: Julia = Jasmine - 6
Ja = A + 7
La = 2 * Ja = 2 A + 14
Li = 3 A
Ju = Ja - 6 = A + 1
all the amounts are relative to each other
... there is no number to set a specific value
To find out the number of each item, we can represent the number of items using variables. Let's assign variables to represent the number of items each person has:
April: A
Jasmine: J
Laura: L
Liam: M
Julia: U
Now, let's translate the given information into equations using the variables:
1. "April has the fewest": This means that April has the smallest number of items among all the people. We don't know the specific number, but we can represent it with the variable A.
2. "Jasmine has 7 more than April": To represent this, we can set up an equation that states that Jasmine's number (J) is equal to April's number (A) plus 7: J = A + 7.
3. "Laura has twice as many as Jasmine": We can set up the equation that states that Laura's number (L) is equal to Jasmine's number (J) multiplied by 2: L = 2J.
4. "Liam has 3 times as many as April": We can set up the equation that states that Liam's number (M) is equal to April's number (A) multiplied by 3: M = 3A.
5. "Julia has 6 fewer than Jasmine": We can set up the equation that states that Julia's number (U) is equal to Jasmine's number (J) minus 6: U = J - 6.
Now you have a system of equations that can be used to solve for the variables A, J, L, M, and U.