Solve: x^2+4x−5=0
which factor of 5 differ by 4?
One will be positive, the other negative.
x^2+4x-5 = 0. -5 = -1*5. -1+5 = 4 = B.
(x-1)(x+5) = 0
x-1 = 0, X = 1.
x+5 = 0, X = -5.
To solve the quadratic equation x^2 + 4x - 5 = 0, we can use the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a),
where a, b, and c are the coefficients of the equation.
In our equation, a = 1, b = 4, and c = -5.
Plugging in these values, we get:
x = (-(4) ± √((4)^2 - 4(1)(-5))) / (2(1)),
Simplifying further:
x = (-4 ± √(16 + 20)) / 2,
x = (-4 ± √36) / 2,
x = (-4 ± 6) / 2.
Therefore, we have two possible solutions:
x1 = (-4 + 6) / 2 = 2 / 2 = 1,
x2 = (-4 - 6) / 2 = -10 / 2 = -5.
So, the solutions to the equation x^2 + 4x - 5 = 0 are x = 1 and x = -5.