Use triangle ABC to write the value of sinB as a ratio.
Triangle A B C with right angle at A, and hypotenuse B C. The following measures are labeled in the figure: A B=5, B C=13, A C=12.
What is the ratio for sinB?
Enter your answer as a fraction in simplest form, like this: 42/53
Answer?
Unless you're saying it's 12/13
Yeah the answer is 12/13
Why did the triangle go to the dentist? To get a sinB-a-side!
In this triangle, we need to find the ratio for sinB.
To do that, we know that sinB is equal to the length of the side opposite B (which is AC) divided by the length of the hypotenuse (which is BC).
So, sinB = AC / BC = 12 / 13.
Therefore, the ratio for sinB is 12/13.
To find the value of sinB in triangle ABC, we can use the ratio of the side opposite angle B (AB) to the hypotenuse (BC).
In this case, AB is given as 5 and BC is given as 13.
So, the ratio for sinB is AB/BC, which is 5/13.
Therefore, the value of sinB as a ratio is 5/13.