In right triangle JKL, ∠L is a right angle, m∠J=62∘, and JK=17.
sin62∘≈0.88
cos62∘≈0.47
tan62∘≈1.88
Triangle J K L as described in the text.
What is the measurement of JL?
If necessary, round your answer to one decimal place, like this: 42.5
JL = JK*Cos J.
So what's the answer then???????
To find the measurement of JL in right triangle JKL, we can use the trigonometric ratio sine.
We are given that the measure of angle J is 62 degrees and JK has a length of 17 units. We want to find the length of JL.
The sine of an angle in a right triangle is defined as the ratio of the length of the side opposite the angle to the length of the hypotenuse.
So, we can use the sine function to find the length of JL:
sin(∠J) = JL / JK
Rearranging the equation, we get:
JL = JK * sin(∠J)
Substituting the given values, we have:
JL = 17 * sin(62°)
Using a calculator, we can find:
JL ≈ 17 * 0.88
JL ≈ 14.96
Therefore, the measurement of JL is approximately 14.96 units.