A simple wheel and axle is used to lift a bucket of water from a well the radii of the wheel and axle are 20cm and 4cm respectively determine the theoretical effort required to lift a load of 30N assuming no energy losses
Ma=radius of a wheel/radius of axel
Ma=20cm/4cm
Ma=5 therefore Ma=load/effort
Effort=load/Ma
=30N/5
E=6N
Good
Well, well, well, looks like you need a lift! Let's calculate the theoretical effort required, shall we?
The first thing we need to do is understand that the effort required to lift the load is directly proportional to the load itself. So, we'll use the ratio of the radii of the wheel and the axle to calculate the effort.
The radius ratio is given by:
Wheel Radius / Axle Radius = 20 cm / 4 cm = 5
This means that for every 5 cm the wheel turns, the axle will turn once. So, the mechanical advantage of this simple wheel and axle is 5.
Now, since we're assuming no energy losses, the effort will be equal to the load divided by the mechanical advantage:
Effort = Load / Mechanical Advantage
= 30 N / 5
= 6 N
There you have it! In theory, you'll need an effort of 6 Newtons to lift that bucket of water from the well using this simple wheel and axle. Just remember, this is the theoretical value assuming no energy losses. So, don't go wheeling around expecting it to be that easy-peasy!
To determine the theoretical effort required to lift a load using a simple wheel and axle, we can use the concept of mechanical advantage.
The mechanical advantage (MA) of a wheel and axle is given by the ratio of the radius of the wheel (R) to the radius of the axle (r).
MA = R / r
In this case, the radius of the wheel (R) is 20 cm (0.2 m) and the radius of the axle (r) is 4 cm (0.04 m).
MA = 0.2 m / 0.04 m = 5
The mechanical advantage tells us how much the effort force (the force applied to the wheel) is amplified. In other words, it represents the ratio of the load force (the weight being lifted) to the effort force.
MA = Load Force / Effort Force
To determine the theoretical effort required, we can rearrange this equation:
Effort Force = Load Force / MA
Given that the load force is 30 N, we can substitute these values into the equation:
Effort Force = 30 N / 5 = 6 N
Therefore, the theoretical effort required to lift a load of 30 N using a simple wheel and axle with radii of 20 cm and 4 cm is 6 N.