A solenoid 10 turns per cm carries a current of 5A flowing through it. What is the magnetic field inside the solenoid?
B = uo n i
uo = 4 pi * 10^-7
n = 1000 turns/meter
i = 5 amps
Amare
A solenoid 10 turns per cm carries a current of 5A flowing through it.the magnetic field inside the solenoid?
100 mT
To find the magnetic field inside the solenoid, we can use Ampere's Law. Ampere's Law states that the magnetic field around a closed loop is directly proportional to the current passing through the loop.
The formula for calculating the magnetic field inside a solenoid is given by:
B = μ₀ * n * I
Where:
B is the magnetic field,
μ₀ is the permeability of free space (4π × 10⁻⁷ T•m/A),
n is the number of turns per unit length (in this case, 10 turns per cm),
I is the current flowing through the solenoid (5A).
To calculate the magnetic field inside the solenoid, we need to convert the number of turns per cm to turns per meter:
1 cm = 0.01 m (since 1 meter = 100 cm)
Therefore,
n = 10 turns per cm * (1/0.01 m) = 1000 turns per meter
Now, we can substitute the values into the formula:
B = (4π × 10⁻⁷ T•m/A) * (1000 turns/m) * (5A)
Calculating this expression will give us the magnetic field inside the solenoid.