f(u)=tan(u) and g(x)=x^3. Find:
f '(u)=
f '(g(x))=
(f∘g)′(x)=
f'(u) = sec^2(u)
f(g) = tan(g) = tan(x^3) ... f'(g(x)) = 3x^2 sec^2(x^3)
since (f∘g)(x) = f(g(x)) now I'm unsure just what you meant on the 2nd problem...
f '(u)=
f '(g(x))=
(f∘g)′(x)=
f(g) = tan(g) = tan(x^3) ... f'(g(x)) = 3x^2 sec^2(x^3)
since (f∘g)(x) = f(g(x)) now I'm unsure just what you meant on the 2nd problem...