What is the theoretic yield of CaO when you have 2.34 g of calcium which reacts with excess oxygen?
Here is formula2Ca(s) + O2(g) → 2CaO(s)
2Ca(s) + O2(g) → 2CaO(s)
Here is a procedure that will work your stoichiometry problems.
Step 1. Write and balance the equation. You've done that.
Step 2. Convert what you have to mols. mols = g/atomic mass = 2.34/40.08=? Estimated 0.06 BUT you should use the correct value.
Step 3. Using the coefficients in the balanced equation, convert mols of what you have to mols of what you want (one of the products)
0.06 mols Ca x (2 mols CaO/2 mols Ca) = approx 0.06 mols CaO
Step 4. Convert step 3 to grams. g = mols x molar mass = about 0.06 x approx 56 = ? This is the theoretical yield in grams
Often problems will ask for a percent yield. In that case just add another step and %yield = (actual yield/theoretical yield)*100 = ?
To determine the theoretical yield of CaO, we need to use stoichiometry, which is the relationship between the amounts of reactants and products in a chemical reaction.
First, we'll need to convert the mass of calcium (Ca) to moles. The molar mass of Ca is 40.08 g/mol.
Given:
Mass of calcium (Ca) = 2.34 g
Molar mass of calcium (Ca) = 40.08 g/mol
Calculating the number of moles of calcium (Ca):
moles = mass / molar mass
moles of Ca = 2.34 g / 40.08 g/mol
Next, we use the balanced equation to determine the stoichiometry ratio between calcium (Ca) and calcium oxide (CaO).
From the balanced equation:
2 moles of Ca reacts with 2 moles of CaO
Since the ratio is 1:1, the number of moles of CaO produced will be the same as the number of moles of Ca.
Therefore, the theoretical yield of CaO will be the same as the number of moles of Ca.
Finally, we can calculate the theoretical yield of CaO by converting moles of Ca to grams of CaO using the molar mass of CaO, which is 56.08 g/mol.
Theoretical yield of CaO = moles of Ca x molar mass of CaO
Theoretical yield of CaO = moles of Ca x 56.08 g/mol
Now, you can substitute the calculated value of moles of Ca to get the final answer.
To determine the theoretical yield of CaO when 2.34 g of calcium reacts with excess oxygen, you need to follow these steps:
Step 1: Determine the molar mass of calcium (Ca) and calcium oxide (CaO).
The molar mass of calcium (Ca) is 40.08 g/mol.
The molar mass of calcium oxide (CaO) is 56.08 g/mol.
Step 2: Calculate the number of moles of calcium (Ca) using the given mass and the molar mass.
Number of moles = Mass / Molar mass
Number of moles of calcium = 2.34 g / 40.08 g/mol
Step 3: Determine the stoichiometry of calcium oxide (CaO) in the balanced equation.
From the balanced equation, 2 moles of calcium react to form 2 moles of calcium oxide. This means that the mole ratio of calcium to calcium oxide is 1:1.
Step 4: Calculate the number of moles of calcium oxide (CaO) formed using the mole ratio from step 3.
Number of moles of calcium oxide = Number of moles of calcium
Step 5: Convert the number of moles of calcium oxide to grams using the molar mass of calcium oxide.
Mass of calcium oxide = Number of moles of calcium oxide × Molar mass of calcium oxide
Step 6: The calculated mass of calcium oxide is the theoretical yield.
By following these steps, you can calculate the theoretical yield of CaO.