Find the midpoint of M of the line segment joining the points C=(3,-7) and D=(-1,1)
average x = (3-1)/2 = 1
average y = (-7+1)/2 = -3
so ( 1, -3 )
C(3, -7), M(x, y), D(-1, 1).
CM = 1/2(CD).
x-3 = (-1-3)/2
X = 1.
y+7 = (1+7)/2
Y =
To find the midpoint of a line segment, you can use the midpoint formula:
Midpoint M = ((x1 + x2) / 2, (y1 + y2) / 2)
Given the points C = (3, -7) and D = (-1, 1), we can substitute the values into the formula to find the midpoint:
x1 = 3
y1 = -7
x2 = -1
y2 = 1
M = ((x1 + x2) / 2, (y1 + y2) / 2)
= ((3 + -1) / 2, (-7 + 1) / 2)
= (2 / 2, -6 / 2)
= (1, -3)
Therefore, the midpoint M of the line segment joining the points C=(3,-7) and D=(-1,1) is M=(1,-3).
To find the midpoint M of the line segment joining the points C=(3,-7) and D=(-1,1), you can use the formula:
Midpoint M = ((x1 + x2)/2, (y1 + y2)/2)
Here, (x1, y1) are the coordinates of point C and (x2, y2) are the coordinates of point D.
So, let's plug in the values:
(x1, y1) = (3, -7)
(x2, y2) = (-1, 1)
Now apply the formula:
Midpoint M = ((3 + -1) / 2, (-7 + 1) / 2)
= (2/2, -6/2)
= (1, -3)
Therefore, the midpoint M of the line segment CD is (1, -3).