/a-block-of-mass-2kg-is-pushed-along-a-table-with-a-constant-velocity-by-a-force-of-5N-when its push is increased to 9N what is the accelaration and the resultant force
The net force causing acceleration is 9-5 = 4
F = ma, so a = 4/2 = 2 m/s^2
To find the acceleration and resultant force, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass. The formula is:
F = m * a
Where:
F is the net force in Newtons (N)
m is the mass of the object in kilograms (kg)
a is the acceleration in meters per second squared (m/s²)
Given:
Mass (m) = 2 kg
Initial force (F1) = 5 N
New force (F2) = 9 N
First, let's calculate the initial acceleration using the initial force:
F1 = m * a1
5 N = 2 kg * a1
a1 = 5 N / 2 kg
a1 = 2.5 m/s²
Now, let's calculate the new acceleration using the new force:
F2 = m * a2
9 N = 2 kg * a2
a2 = 9 N / 2 kg
a2 = 4.5 m/s²
Therefore, when the force is increased to 9N, the acceleration is 4.5 m/s².
Now, to find the resultant force, we can subtract the initial force from the new force:
Resultant Force = New Force - Initial Force
Resultant Force = 9 N - 5 N
Resultant Force = 4 N
Therefore, the resultant force acting on the block when the force is increased to 9N is 4 Newtons (N).