A fun seeker begins sliding from the top of a water slide and accelerates uniformly at 0.56 m.s-2. If the slide is 36 m long, how long will it take them to reach the bottom?
distance=1/2 a t^2
time= sqrt (2*d/a)=sqrt(2*.56/36) seconds
87.11?
To find the time it takes for the fun seeker to reach the bottom of the water slide, you need to use the equation:
distance = initial velocity × time + 0.5 × acceleration × time^2
In this case, the initial velocity is 0 m/s because the fun seeker starts from rest. The acceleration is 0.56 m/s², and the distance is 36 m.
Plugging in the values:
36 = 0 × t + 0.5 × 0.56 × t^2
Simplifying the equation:
36 = 0.28t^2
Divide both sides by 0.28:
t^2 = 36 / 0.28
t^2 ≈ 128.57
Taking the square root of both sides to find the time:
t ≈ √128.57
t ≈ 11.34 seconds
Therefore, it will take approximately 11.34 seconds for the fun seeker to reach the bottom of the water slide.