The energy-separation curve for two atoms, a distance, r, apart is: U(r)=−Arm+Brn

1) Derive an expression for the equilibrium spacing, r0, as a function of A, B, m, and n. Explicitly indicate multiplication with a * symbol.

r0 = ??

2) Derive and expression for the stiffness of the bond at the equilibrium spacing, in terms of A , B , m , n , and r0 .

S=dFdr at r=r0 :

Derive and expression for the stiffness of the bond at the equilibrium spacing, in terms of A , B , m , n , and r0 .

S=dFdr at r=r0 :

To derive the expression for the equilibrium spacing, r0, as a function of A, B, m, and n, we need to find the point where the energy-separation curve is at its minimum.

1) Equilibrium spacing, r0:
The equilibrium spacing occurs when the energy is at its minimum. In other words, it's the value of r where the derivative of U(r) with respect to r is equal to zero:

dU/dr = 0

To find the derivative, we differentiate the equation U(r) with respect to r term by term:

dU/dr = -(Amr^(m-1)) + (Brn-1)

Setting this derivative equal to zero, we can solve for r:

-(Amr^(m-1)) + (Brn-1) = 0

Amr^(m-1) = Brn-1

Dividing both sides of the equation by Am:

r^(m-1) = (B/A) * r^(n-1)

Now, we can isolate r:

r0^(m-1) = (B/A) * r0^(n-1)

Dividing both sides by r0^(n-1):

r0^(m-1-n+1) = (B/A)

Simplifying:

r0^(m-n) = (B/A)

Finally, taking the (m-n)th root of both sides:

r0 = (B/A)^(1/(m-n))

So, the expression for the equilibrium spacing, r0, as a function of A, B, m, and n is:

r0 = (B/A)^(1/(m-n))

2) Stiffness of the bond, S, at equilibrium spacing:
To find the stiffness of the bond at the equilibrium spacing, we need to calculate the derivative of the force with respect to r at r=r0.

S = dF/dr at r=r0

The force is the negative derivative of the energy:

F = -dU/dr

Differentiating the equation U(r) with respect to r:

F = Amr^(m-1) - Brn-1

Now, let's differentiate F with respect to r:

dF/dr = d/dx (Amr^(m-1) - Brn-1)

dF/dr = Am(m-1)r^(m-2) - Bn(n-1)r^(n-2)

Now, we can evaluate dF/dr at r=r0:

S = dF/dr at r=r0 = Am(m-1)r0^(m-2) - Bn(n-1)r0^(n-2)

So, the expression for the stiffness of the bond at the equilibrium spacing, in terms of A, B, m, n, and r0 is:

S = Am(m-1)r0^(m-2) - Bn(n-1)r0^(n-2)