find the zeroes of g(x)=x^2−11x+10.
factor...
___ x ___ = 10
___ + ___ = -11
what are -10 and -1
you do the rest : )
x^2-11x+10 = 0
10 = -1*(-10). sum = -11 = B.
(x-1)(x-19) = 0
x-1 = 0, X = 1.
x-10 = 0, X =
To find the zeros of the quadratic function g(x) = x^2 - 11x + 10, we need to find the values of x for which g(x) equals zero.
In general, a quadratic equation in the form ax^2 + bx + c = 0 can be solved using the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In the given equation g(x) = x^2 - 11x + 10, we have a = 1, b = -11, and c = 10. Substituting these values into the quadratic formula, we get:
x = (-(-11) ± √((-11)^2 - 4(1)(10))) / (2(1))
= (11 ± √(121 - 40)) / 2
= (11 ± √81) / 2
Now, we simplify further:
x = (11 ± 9) / 2
This gives us two possible solutions:
x1 = (11 + 9) / 2 = 20 / 2 = 10
x2 = (11 - 9) / 2 = 2 / 2 = 1
Therefore, the zeroes of g(x) = x^2 - 11x + 10 are x = 10 and x = 1.