A 1 kg block of ice at 0 celcius is added to a picnic cooler. How much heat will the ice remove as it melts to water at 0 celcius
Hey, what is the heat of fusion of water? You know it but if not Google it.
You are at zero deg C, the melting/freezing point
Therefore all you have to do is multiply the mass by the heat of fusion.
Make sure your units are Joules and kilograms.
To calculate the amount of heat that will be removed as the block of ice melts to water at 0 degrees Celsius, you can use the formula:
Q = m * L
Where:
Q is the heat energy (in joules)
m is the mass of the ice (in kilograms)
L is the latent heat of fusion for ice (in joules per kilogram)
In this case, the mass of the ice is given as 1 kg, and the latent heat of fusion for ice is approximately 334,000 joules per kilogram.
Plugging these values into the formula, we can calculate the heat energy:
Q = 1 kg * 334,000 J/kg
Q = 334,000 Joules
Therefore, the ice will remove 334,000 joules of heat energy as it melts to water at 0 degrees Celsius.