How does the size of a cell’s surface area change compared to its volume when the cell grows?

a. The surface area remains constant as the volume changes.
b. The surface area increases at the same rate the volume does.
c. The surface area increases faster than the volume does.
d. The surface area does not increase as fast as the volume does.

When a cell grows, its volume increases faster than its surface area. As a result, the ratio of surface area to volume decreases. This means that the surface area does not increase as fast as the volume does. Therefore, the correct answer is d. The surface area does not increase as fast as the volume does.

To determine how the size of a cell's surface area changes in comparison to its volume when it grows, we need to understand the relationship between surface area and volume in a three-dimensional object.

In a cell, surface area refers to the area of the external membrane or outer surface, while volume refers to the space enclosed by the cell membrane. As the cell grows, both the surface area and volume increase, but they do not increase at the same rate.

The surface area of an object is proportional to the square of its size, while the volume is proportional to the cube of its size. In other words, when the dimensions of an object increase, the surface area grows by a factor of the square of the dimension, whereas the volume grows by a factor of the cube of the dimension.

Therefore, as a cell grows, its volume increases more rapidly than its surface area. This means that the surface area does not increase as fast as the volume. In other words, the correct answer is option d: "The surface area does not increase as fast as the volume does."

As the cell increases in size, the volume of the cell also increases and so does the surface area.

so the answer is b.

I think it's actually d