I need help quickly please!
Silver is one of the best conductors of electricity and used in the electrical wiring for high-end stereo equipment. Determine the mass of the silver if the wire absorbs 3.45 x 103 J of energy at 23.0° C and is heated to 69.0° C after carrying a current for two hours. [The specific heat of silver is 0.230 J/g C]
Please show work!!
q = mass Ag x specific heat Ag x (Tfinal-Tinitial) = ?
To determine the mass of the silver wire, we can use the formula:
q = mcΔT
where q is the heat absorbed, m is the mass, c is the specific heat, and ΔT is the change in temperature.
Given:
q = 3.45 x 10^3 J (energy absorbed)
ΔT = 69.0°C - 23.0°C = 46.0°C (change in temperature)
c = 0.230 J/g°C (specific heat)
Now we can rearrange the formula to solve for the mass (m):
m = q / (c * ΔT)
Substituting the given values:
m = 3.45 x 10^3 J / (0.230 J/g°C * 46.0°C)
m = 3.45 x 10^3 J / 10.58 J/g
m ≈ 326.78 g
Therefore, the mass of the silver wire is approximately 326.78 grams.
To determine the mass of the silver wire, we can use the specific heat formula:
Q = m * c * ΔT
Where:
Q is the heat absorbed by the wire (in Joules),
m is the mass of the wire (in grams),
c is the specific heat of silver (in J/g C),
ΔT is the change in temperature of the wire (in Celsius).
In this case, we know:
Q = 3.45 x 10^3 J
c = 0.230 J/g C
ΔT = 69.0 - 23.0 = 46.0 C
Now we can rearrange the formula to solve for mass (m):
m = Q / (c * ΔT)
Substituting the given values:
m = 3.45 x 10^3 J / (0.230 J/g C * 46.0 C)
m = 3.45 x 10^3 J / 10.58 J/g
m ≈ 326.30 g
Therefore, the mass of the silver wire is approximately 326.30 grams.