Water freezes completely at 0.00° C, giving off 12.0 kcal of heat. What is the mass of the water? (heat of fusion (∆Hf) = 80.0 cal/g)
Please show work
mass H2O x heat fusion @ 0.00 C = q
mass H2O x 80 cal/g = 12,000 cal
To find the mass of water, you can use the relationship between heat and heat of fusion, along with the given values.
First, let's convert the given heat of fusion (∆Hf) from calories to kcal:
∆Hf = 80.0 cal/g = 0.08 kcal/g
We know that when water freezes, it releases 12.0 kcal of heat. So, we can set up the following equation:
heat released = ∆Hf × mass of water
Solving for mass of water:
mass of water = heat released / ∆Hf
Substituting the given values:
mass of water = 12.0 kcal / 0.08 kcal/g
mass of water = 150 g
Therefore, the mass of water is 150 grams.